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Averages · Question 60 of 62

Question 60

HardOriginal question

Before a match, a bowler's bowling average was 24.5 runs per wicket. In the match he took 5 wickets for 26 runs, and his bowling average improved to 24. How many wickets had he taken before the match?

Options for question 60

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. Let w be the wickets before the match. Runs conceded before = 24.5w.

  2. After the match: 24.5w+26=24(w+5)24.5w + 26 = 24(w + 5).

  3. 0.5w=120−26=940.5w = 120 - 26 = 94, so w=188w = 188.

Worth noting

94 forgets to divide by 0.5; 193 is the total after the match. Bowling average = runs conceded ÷ wickets, so lower is better.

Concept
Bowling average: runs conceded per wicket
Typical time
110 s
Your time
—
The rule this testsChange in average
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Ten questions from Averages, at your own pace.

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