A die is thrown 4 times. What is the probability of at least one six?

\frac{625}{1296}

Correct answerYour answer

\frac{671}{1296}

Correct answerYour answer

\frac{2}{3}

Correct answerYour answer

\frac{1967}{2592}

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer B

Correct answer: B

'At least one six' is the complement of 'no six': $1 - \left(\frac{5}{6}\right)^{4}$ .
$= 1 - \frac{625}{1{,}296} = \frac{671}{1{,}296}$ .

Worth noting

$\frac{4}{6}$ adds $\frac{1}{6}$ four times, which double-counts throws with more than one six.

Ten questions from Binomial & Poisson Distributions, at your own pace.

Ten questions from Binomial & Poisson Distributions, at your own pace.

Explanation