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Chain Rule, Log Differentiation & Rate of Change · Question 111 of 130

Question 111

EasyOriginal question

The radius of a circular patch of paint grows at 0.3 cm/s. How fast is its area growing when the radius is 10 cm?

Options for question 111

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. dAdt=2πrdrdt\frac{dA}{dt} = 2\pi r\frac{dr}{dt}.

  2. 2π×10×0.3=6π2\pi \times 10 \times 0.3 = 6\pi cm²/s.

Worth noting

20π20\pi is dAdr\frac{dA}{dr}, before multiplying by 0.3.

Concept
A rate of change through a related quantity
Typical time
60 s
Your time
—
The rule this testsRate of change of quantities
Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.

Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.