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EMI, CAGR & Depreciation · Question 25 of 66

Question 25

HardOriginal question

A loan of ₹50,000 at 10% a year is repaid in 2 equal yearly instalments by the reducing-balance method. To the nearest rupee, what is each instalment? (Take (1.1)2=1.21(1.1)^{2} = 1.21.)

Options for question 25

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. E=50,000×0.1×1.211.21−1=6,0500.21E = \frac{50{,}000 \times 0.1 \times 1.21}{1.21 - 1} = \frac{6{,}050}{0.21}.

  2. E≈28,810E \approx 28{,}810 rupees.

Worth noting

₹30,000 charges a flat ₹5,000 of interest each year, but in the second year only about half the loan is still owed.

Concept
A yearly instalment by reducing balance
Typical time
120 s
Your time
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The rule this testsEMI by the reducing-balance method
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Ten questions from EMI, CAGR & Depreciation, at your own pace.

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Ten questions from EMI, CAGR & Depreciation, at your own pace.