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EMI, CAGR & Depreciation · Question 59 of 66

Question 59

MediumOriginal question

An asset costs ₹50,000 and will be sold for scrap at ₹5,000. It is depreciated by ₹4,500 a year by the linear method. What is its useful life?

Options for question 59

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. Useful life = (cost − residual value) ÷ yearly depreciation.

  2. 50,000−5,0004,500=45,0004,500=10\frac{50{,}000 - 5{,}000}{4{,}500} = \frac{45{,}000}{4{,}500} = 10 years.

Worth noting

11.11 years divides the whole cost, forgetting the scrap value.

Concept
Useful life from the depreciation
Typical time
90 s
Your time
—
The rule this testsLinear depreciation
Practise this chapter →

Ten questions from EMI, CAGR & Depreciation, at your own pace.

Practise this chapter →

Ten questions from EMI, CAGR & Depreciation, at your own pace.