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Matrices · Question 37 of 106

Question 37

EasyOriginal question

If A=[3−124]A = \begin{bmatrix}3 & -1 \\ 2 & 4\end{bmatrix} and B=[120−1]B = \begin{bmatrix}1 & 2 \\ 0 & -1\end{bmatrix}, what is 2A−3B2A - 3B?

Options for question 37

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. Multiply each matrix by its scalar, element by element: 2A=[6−248]2A = \begin{bmatrix} 6 & -2 \\ 4 & 8 \end{bmatrix}, 3B=[360−3]3B = \begin{bmatrix} 3 & 6 \\ 0 & -3 \end{bmatrix}.

  2. Subtract: [3−8411]\begin{bmatrix}3 & -8 \\ 4 & 11\end{bmatrix}.

Worth noting

Subtracting −3-3 gives +3+3: the last element is 8−(−3)=118 - (-3) = 11.

Concept
Adding and scaling matrices
Typical time
60 s
Your time
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The rule this testsAddition and multiplication by a scalar
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Ten questions from Matrices, at your own pace.

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Ten questions from Matrices, at your own pace.