A day's temperature stays between 86 °F and 95 °F. Using C = 5/9(F - 32), what is the range in °C?

Numerical Inequalities · Question 70 of 79

Question 70

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A day's temperature stays between 86 °F and 95 °F. Using $C = \frac{5}{9}(F - 32)$ , what is the range in °C?

Between 30 °C and 36 °CCorrect answerYour answerBetween 48 °C and 53 °CCorrect answerYour answerBetween 25 °C and 30 °CCorrect answerYour answerBetween 30 °C and 35 °CCorrect answerYour answer

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CorrectNot quiteAnswer D

Correct answer: D

$86 < F < 95$ gives $54 < F - 32 < 63$ .
Multiplying by $\frac{5}{9}$ : $30 < C < 35$ .

Worth noting

48 °C to 53 °C forgets to subtract 32 before scaling.

Concept: Converting a range
Typical timeTypical: 90 s
Your timeYours: —

The rule this testsInequalities from situations

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A day's temperature stays between 86 °F and 95 °F. Using C=59(F−32)C = \frac{5}{9}(F - 32)C=95​(F−32), what is the range in °C?

Explanation

A day's temperature stays between 86 °F and 95 °F. Using $C = \frac{5}{9}(F - 32)$ , what is the range in °C?