EduFarming
Your list · 0हिं

Type at least two letters. Press Esc to close.

↑↓ navigate↵ openTAB cycle filter

Random Variables, Expectation & Variance · Question 17 of 68

Question 17

EasyOriginal question

P(X=x)=k(x+1)P(X = x) = k(x + 1) for x=0,1,2,3x = 0, 1, 2, 3, and 0 otherwise. What is kk?

Options for question 17

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. The probabilities must add up to 1: k(1+2+3+4)=10k=1k(1 + 2 + 3 + 4) = 10k = 1.

  2. k=110k = \frac{1}{10}.

Worth noting

16\frac{1}{6} adds 0+1+2+30 + 1 + 2 + 3, using kxkx instead of k(x+1)k(x + 1).

Concept
Finding the constant in a distribution
Typical time
60 s
Your time
—
The rule this testsProbability distributions
Practise this chapter →

Ten questions from Random Variables, Expectation & Variance, at your own pace.

Practise this chapter →

Ten questions from Random Variables, Expectation & Variance, at your own pace.