A sample of 36 has mean 82 and standard deviation 12. What is the t-value for testing $H_0: \mu = 80$?

Explanation

1. 01

   $t = \frac{\bar{x} - \mu}{s/\sqrt{n}} = \frac{82 - 80}{12/\sqrt{36}}$.

2. 02

   $= \frac{2}{2} = 1$.