What is the vector form of the line (x - 5)/3 = (y + 4)/7 = (z - 6)/2?

r = (5 i - 4 j + 6 k) + λ(3 i + 7 j + 2 k)

r = (5 i + 4 j + 6 k) + λ(3 i + 7 j + 2 k)

r = (3 i + 7 j + 2 k) + λ(5 i - 4 j + 6 k)

r = (-5 i + 4 j - 6 k) + λ(3 i + 7 j + 2 k)

Question 41

MediumOriginal question

What is the vector form of the line $\frac{x - 5}{3} = \frac{y + 4}{7} = \frac{z - 6}{2}$ ?

\vec{r} = (5\hat{i} + 4\hat{j} + 6\hat{k}) + \lambda(3\hat{i} + 7\hat{j} + 2\hat{k})

Correct answerYour answer

\vec{r} = (5\hat{i} - 4\hat{j} + 6\hat{k}) + \lambda(3\hat{i} + 7\hat{j} + 2\hat{k})

Correct answerYour answer

\vec{r} = (3\hat{i} + 7\hat{j} + 2\hat{k}) + \lambda(5\hat{i} - 4\hat{j} + 6\hat{k})

Correct answerYour answer

\vec{r} = (-5\hat{i} + 4\hat{j} - 6\hat{k}) + \lambda(3\hat{i} + 7\hat{j} + 2\hat{k})

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer B

Correct answer: B

Worth noting

$y + 4$ means $y_1 = -4$ , not 4.

Ten questions from Three-Dimensional Geometry, at your own pace.