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Three-Dimensional Geometry · Question 116 of 120

Question 116

HardOriginal question

What is the distance between the lines r⃗=(i^+2j^−k^)+λ(2i^−j^+2k^)\vec{r} = (\hat{i} + 2\hat{j} - \hat{k}) + \lambda(2\hat{i} - \hat{j} + 2\hat{k}) and r⃗=(3i^−j^+k^)+μ(−4i^+2j^−4k^)\vec{r} = (3\hat{i} - \hat{j} + \hat{k}) + \mu(-4\hat{i} + 2\hat{j} - 4\hat{k})?

Options for question 116

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. −4i^+2j^−4k^=−2(2i^−j^+2k^)-4\hat{i} + 2\hat{j} - 4\hat{k} = -2(2\hat{i} - \hat{j} + 2\hat{k}): the lines are parallel, so use one direction b⃗=2i^−j^+2k^\vec{b} = 2\hat{i} - \hat{j} + 2\hat{k}, with ∣b⃗∣=3\lvert \vec{b} \rvert = 3.

  2. b⃗×(a⃗2−a⃗1)=(2i^−j^+2k^)×(2i^−3j^+2k^)=4i^−4k^\vec{b} \times (\vec{a}_2 - \vec{a}_1) = (2\hat{i} - \hat{j} + 2\hat{k}) \times (2\hat{i} - 3\hat{j} + 2\hat{k}) = 4\hat{i} - 4\hat{k}, of length 424\sqrt{2}.

  3. d=423d = \frac{4\sqrt{2}}{3}.

Worth noting

823\frac{8\sqrt{2}}{3} crosses with −4i^+2j^−4k^-4\hat{i} + 2\hat{j} - 4\hat{k} but divides by the length of 2i^−j^+2k^2\hat{i} - \hat{j} + 2\hat{k}.

Concept
The distance between parallel lines
Typical time
120 s
Your time
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The rule this testsSkew lines and the shortest distance
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Ten questions from Three-Dimensional Geometry, at your own pace.

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Ten questions from Three-Dimensional Geometry, at your own pace.