The average of 12 numbers is 45. When two of the numbers are removed, the average of the remaining 10 numbers is 44. What is the average of the two numbers removed?

Explanation

1. 01

   Total of $12 = 12 \times 45 = 540$.

2. 02

   Total of remaining $10 = 10 \times 44 = 440$.

3. 03

   The two removed numbers add up to 100, so their average is 50.