A taxi charges a fixed fare plus a fixed amount for every kilometre. A 10 km ride costs ₹230 and a 16 km ride costs ₹338. What is the fixed fare?

₹18Correct answerYour answer₹23Correct answerYour answer₹50Correct answerYour answer₹108Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

Let the fixed fare be ₹ $c$ and the rate ₹ $r$ per km: $c + 10r = 230$ and $c + 16r = 338$ .
Subtract: $6r = 108$ , so $r = 18$ .
Then $c = 230 - 180 = 50$ , i.e. ₹50.

Worth noting

₹18 is the per-km rate and ₹23 is simply $230 \div 10$ , which ignores the fixed part. ₹108 is the cost of the extra 6 km.

Ten questions from Linear and Quadratic Equations, at your own pace.

Explanation