The mean score of 8 contestants in a quiz was 30. Two latecomers joined, one scoring twice as much as the other, and the mean of all 10 contestants became 36. What did the higher-scoring latecomer score?

Explanation

1. 01

   Old total = $8 \times 30 = 240$. New total = $10 \times 36 = 360$.

2. 02

   The two latecomers scored $360 - 240 = 120$ together: $x + 2x = 120$, so $x = 40$.

3. 03

   The higher score is $2 \times 40 = 80$.