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Number System · Question 33 of 71

Question 33

MediumOriginal question

Salma's locker code is the four-digit number 37☐5, and she remembers that it is divisible by 25. What is the sum of all digits that could go in the box?

Options for question 33

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. A number is divisible by 25 when its last two digits are 00, 25, 50 or 75.

  2. The last two digits are ☐5, so they must be 25 or 75: ☐ is 2 or 7.

  3. Sum of the possible digits = 2+7=92 + 7 = 9.

Worth noting

2 and 7 are each possible; the question asks for their sum.

Concept
Divisibility rule for 25
Typical time
55 s
Your time
—
The rule this testsDivisibility rules
Practise this chapter →

Ten questions from Number System, at your own pace.

Practise this chapter →

Ten questions from Number System, at your own pace.