A die is thrown 3 times. What is the probability of at least one six?

Explanation

1. 01

   'At least one' is the complement of 'none'. The chance of no six is $\left(\frac{5}{6}\right)^{3} = \frac{125}{216}$.

2. 02

   So the chance of at least one six is $1 - \frac{125}{216} = \frac{91}{216}$.