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Binomial & Poisson Distributions · Question 36 of 68

Match each quantity in List I with its value in List II.

Question 36

MediumOriginal question

Match each quantity in List I with its value in List II.

List IList II
A. Mean of a binomial distribution with n=10n = 10, p=0.5p = 0.5I. 44
B. Variance of a binomial distribution with n=10n = 10, p=0.5p = 0.5II. 55
C. Variance of a Poisson distribution with λ=4\lambda = 4III. 33
D. Standard deviation of a Poisson distribution with λ=9\lambda = 9IV. 2.52.5
Options for question 36

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. Binomial: mean np=5np = 5, variance npq=10×0.5×0.5=2.5npq = 10 \times 0.5 \times 0.5 = 2.5.

  2. Poisson: the variance equals λ=4\lambda = 4; with λ=9\lambda = 9 the standard deviation is 9=3\sqrt{9} = 3.

Concept
Means and variances of the two distributions
Typical time
120 s
Your time
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The rule this testsMean and variance of a binomial distribution
Practise this chapter →

Ten questions from Binomial & Poisson Distributions, at your own pace.

Practise this chapter →

Ten questions from Binomial & Poisson Distributions, at your own pace.