$X$ follows a Poisson distribution with $\lambda = 2$. What is $P(X = 2)$? (Take $e^{-2} = 0.1353$.)

Explanation

1. 01

   $P(X = 2) = \frac{e^{-2} \times 2^{2}}{2!} = \frac{4}{2} \times 0.1353$.

2. 02

   $= 2 \times 0.1353 = 0.2706$.