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Binomial & Poisson Distributions · Question 54 of 68

Question 54

MediumOriginal question

Calls reach a help desk at an average of 2 a minute, following a Poisson distribution. What is the probability of no call in a given minute? (Take e−2=0.1353e^{-2} = 0.1353.)

Options for question 54

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. P(X=0)=e−λλ00!=e−λP(X = 0) = \frac{e^{-\lambda}\lambda^{0}}{0!} = e^{-\lambda}.

  2. With λ=2\lambda = 2: e−2=0.1353e^{-2} = 0.1353.

Worth noting

0.8647 is the probability of at least one call.

Concept
The probability of no event
Typical time
90 s
Your time
—
The rule this testsThe Poisson distribution
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