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Binomial & Poisson Distributions · Question 68 of 68

What is the probability that a box of bulbs has two or more defective bulbs?

Question 68

HardOriginal question

A factory finds that 5% of its LED bulbs are defective. They are packed in boxes of 10, and the number of defective bulbs in a box is taken to follow a Poisson distribution. (Take e−0.5=0.6065e^{-0.5} = 0.6065.)

What is the probability that a box of bulbs has two or more defective bulbs?

Options for question 68

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. P(X≥2)=1−P(0)−P(1)P(X \ge 2) = 1 - P(0) - P(1).

  2. 1−0.6065−0.30325=0.090251 - 0.6065 - 0.30325 = 0.09025.

Worth noting

0.0758125 is exactly two; 'two or more' takes in every larger count as well.

Concept
At least two, through the complement
Typical time
150 s
Your time
—
The rule this testsThe Poisson distribution
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