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Binomial & Poisson Distributions · Question 67 of 68

Question 67

HardOriginal question

For a Poisson variable XX, P(X=1)=P(X=2)P(X = 1) = P(X = 2). What is its mean?

Options for question 67

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. e−λλ=e−λλ22e^{-\lambda}\lambda = \frac{e^{-\lambda}\lambda^{2}}{2}.

  2. Dividing by e−λλe^{-\lambda}\lambda: 1=λ21 = \frac{\lambda}{2}, so λ=2\lambda = 2, which is the mean.

Worth noting

1 forgets the 2!2! under λ2\lambda^{2}.

Concept
The mean from a condition
Typical time
120 s
Your time
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The rule this testsThe Poisson distribution
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Ten questions from Binomial & Poisson Distributions, at your own pace.

Practise this chapter →

Ten questions from Binomial & Poisson Distributions, at your own pace.