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Binomial & Poisson Distributions · Question 66 of 68

Question 66

HardOriginal question

1% of the screws a machine makes are faulty. Using the Poisson distribution, what is the probability that a box of 300 screws has no faulty screw? (Take e−3=0.0498e^{-3} = 0.0498.)

Options for question 66

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. For many trials with a small chance, use Poisson with λ=np=300×0.01=3\lambda = np = 300 \times 0.01 = 3.

  2. P(X=0)=e−3=0.0498P(X = 0) = e^{-3} = 0.0498.

Worth noting

0.99 is the chance that one screw is good, not all 300.

Concept
Poisson as an approximation to the binomial
Typical time
120 s
Your time
—
The rule this testsThe Poisson distribution
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Ten questions from Binomial & Poisson Distributions, at your own pace.

Practise this chapter →

Ten questions from Binomial & Poisson Distributions, at your own pace.