X follows a Poisson distribution with λ = 1. What is P(X ≥ 2)? (Take e^-1 = 0.3679.)

Binomial & Poisson Distributions · Question 65 of 68

Question 65

HardOriginal question

$X$ follows a Poisson distribution with $\lambda = 1$ . What is $P(X \ge 2)$ ? (Take $e^{-1} = 0.3679$ .)

- \frac{3679}{5000}

Correct answerYour answer

0.18395

Correct answerYour answer

0.2642

Correct answerYour answer

0.6321

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

$P(X \ge 2) = 1 - P(X = 0) - P(X = 1)$ , and with $\lambda = 1$ both are $e^{-1} = 0.3679$ .
$= 1 - 0.7358 = 0.2642$ .

Worth noting

0.6321 takes away only $P(X = 0)$ ; that is $P(X \ge 1)$ .

Ten questions from Binomial & Poisson Distributions, at your own pace.

Ten questions from Binomial & Poisson Distributions, at your own pace.