A die is thrown 4 times. What is the probability of exactly 2 sixes?

\frac{25}{1296}

Correct answerYour answer

\frac{1}{36}

Correct answerYour answer

\frac{25}{216}

Correct answerYour answer

\frac{1}{3}

Correct answerYour answer

Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

$P(X = 2) = {}^{4}C_2\left(\frac{1}{6}\right)^{2}\left(\frac{5}{6}\right)^{2}$ .
$= 6 \times \frac{25}{1{,}296} = \frac{25}{216}$ .

Worth noting

$\frac{25}{1{,}296}$ leaves out ${}^{4}C_2 = 6$ , the number of ways to place the two sixes.

Ten questions from Binomial & Poisson Distributions, at your own pace.

Ten questions from Binomial & Poisson Distributions, at your own pace.

Explanation