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Binomial & Poisson Distributions · Question 44 of 68

Question 44

HardOriginal question

A binomial distribution has mean 4 and variance 3. What is P(X=0)P(X = 0)?

Options for question 44

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. q=34q = \frac{3}{4}, so p=14p = \frac{1}{4} and n=41/4=16n = \frac{4}{1/4} = 16.

  2. P(X=0)=qn=(34)16P(X = 0) = q^{n} = \left(\frac{3}{4}\right)^{16}.

Worth noting

(14)16\left(\frac{1}{4}\right)^{16} is P(X=16)P(X = 16), every trial a success.

Concept
A probability from the mean and variance
Typical time
120 s
Your time
—
The rule this testsMean and variance of a binomial distribution
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Ten questions from Binomial & Poisson Distributions, at your own pace.

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Ten questions from Binomial & Poisson Distributions, at your own pace.