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Binomial & Poisson Distributions · Question 58 of 68

Question 58

MediumOriginal question

XX follows a Poisson distribution with λ=1.5\lambda = 1.5. What is P(X≤1)P(X \le 1)? (Take e−1.5=0.2231e^{-1.5} = 0.2231.)

Options for question 58

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. P(X≤1)=P(0)+P(1)=e−1.5(1+1.5)P(X \le 1) = P(0) + P(1) = e^{-1.5}(1 + 1.5).

  2. =0.2231×2.5=0.55775= 0.2231 \times 2.5 = 0.55775.

Worth noting

0.33465 is P(X=1)P(X = 1) alone.

Concept
At most r events
Typical time
90 s
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Ten questions from Binomial & Poisson Distributions, at your own pace.

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Ten questions from Binomial & Poisson Distributions, at your own pace.