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Conditional Probability & Bayes' Theorem · Question 102 of 125

Question 102

EasyOriginal question

P(E)=0.2P(E) = 0.2, P(A∣E)=0.5P(A \mid E) = 0.5 and P(A)=0.25P(A) = 0.25. What is P(E∣A)P(E \mid A)?

Options for question 102

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. P(E∣A)=P(E) P(A∣E)P(A)P(E \mid A) = \frac{P(E)\,P(A \mid E)}{P(A)}.

  2. 0.2×0.50.25=0.10.25=0.4\frac{0.2 \times 0.5}{0.25} = \frac{0.1}{0.25} = 0.4.

Worth noting

0.1 is P(E∩A)P(E \cap A), the numerator, before dividing by P(A)P(A).

Concept
Bayes' theorem from given probabilities
Typical time
60 s
Your time
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The rule this testsBayes' theorem
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Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.

Practise this chapter →

Ten questions from Conditional Probability & Bayes' Theorem, at your own pace.