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Continuity & Differentiability · Question 116 of 125

Question 116

HardOriginal question

At how many points is f(x)=∣sin⁡x∣f(x) = \lvert \sin x \rvert on (0,2π)(0, 2\pi) not differentiable?

Options for question 116

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. sin⁡x=0\sin x = 0 inside (0,2π)(0, 2\pi) only at x=πx = \pi.

  2. There ∣sin⁡x∣\lvert \sin x \rvert has a corner: 1 point.

Worth noting

2 or 3 count 0 and 2π2\pi, which the open interval leaves out.

Concept
Counting points where a function is not differentiable
Typical time
120 s
Your time
—
The rule this testsDifferentiability
Practise this chapter →

Ten questions from Continuity & Differentiability, at your own pace.

Practise this chapter →

Ten questions from Continuity & Differentiability, at your own pace.