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Continuity & Differentiability · Question 72 of 125

Question 72

MediumOriginal question

Let f(x)=1xf(x) = \frac{1}{x} and g(x)=1x−1g(x) = \frac{1}{x - 1}. What is the set of all points at which f∘gf \circ g is continuous?

Options for question 72

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. f(g(x))f(g(x)) needs g(x)g(x) to be defined, so x≠1x \ne 1, and g(x)≠0g(x) \ne 0, which always holds.

  2. On that domain f(g(x))=x−1f(g(x)) = x - 1, a polynomial, so f∘gf \circ g is continuous on R−{1}\mathbb{R} - \{1\}.

Worth noting

R\mathbb{R} simplifies f(g(x))f(g(x)) to x−1x - 1 and forgets that g(1)g(1) is not defined.

Concept
Where a function is continuous
Typical time
90 s
Your time
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The rule this testsContinuous functions
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Ten questions from Continuity & Differentiability, at your own pace.

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Ten questions from Continuity & Differentiability, at your own pace.