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Derivatives & Second-Order Derivatives · Question 16 of 96

Question 16

MediumOriginal question

What is the derivative of sin⁡xx\frac{\sin x}{x}?

Options for question 16

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. Quotient rule: (uv)′=u′v−uv′v2\left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^2}, with u=sin⁡xu = \sin x and v=xv = x.

  2. This simplifies to xcos⁡x−sin⁡xx2\frac{x \cos x - \sin x}{x^{2}}.

Worth noting

−xcos⁡x+sin⁡xx2\frac{- x \cos x + \sin x}{x^{2}} has the numerator the wrong way round: it is u′v−uv′u'v - uv', not uv′−u′vuv' - u'v.

Concept
The quotient rule
Typical time
90 s
Your time
—
The rule this testsThe rules of differentiation
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Ten questions from Derivatives & Second-Order Derivatives, at your own pace.

Practise this chapter →

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.