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Derivatives & Second-Order Derivatives · Question 85 of 96

Question 85

MediumOriginal question

If y=e2x+e−2xy = e^{2 x} + e^{- 2 x} and d2ydx2=ky\frac{d^2y}{dx^2} = ky, what is kk?

Options for question 85

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. dydx=2e2x−2e−2x\frac{dy}{dx} = 2 e^{2 x} - 2 e^{- 2 x}.

  2. d2ydx2=4(e4x+1)e−2x\frac{d^2y}{dx^2} = 4 \left(e^{4 x} + 1\right) e^{- 2 x}, which is 4y4y.

Worth noting

2 comes from differentiating once; the factor 2 comes out a second time.

Concept
Second derivatives of exponentials
Typical time
90 s
Your time
—
The rule this testsEquations with second derivatives
Practise this chapter →

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.

Practise this chapter →

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.