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Derivatives & Second-Order Derivatives · Question 21 of 96

Question 21

MediumOriginal question

g(1)=4g(1) = 4, g′(1)=3g'(1) = 3, h(1)=2h(1) = 2 and h′(1)=−1h'(1) = -1. If f(x)=g(x)h(x)f(x) = \frac{g(x)}{h(x)}, what is f′(1)f'(1)?

Options for question 21

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. f′(1)=g′(1)h(1)−g(1)h′(1)[h(1)]2f'(1) = \frac{g'(1)h(1) - g(1)h'(1)}{[h(1)]^{2}}.

  2. =(3)(2)−(4)(−1)4=104=52= \frac{(3)(2) - (4)(-1)}{4} = \frac{10}{4} = \frac{5}{2}.

Worth noting

−52-\frac{5}{2} puts the numerator the wrong way round, gh′−g′hgh' - g'h.

Concept
The quotient rule from given values
Typical time
90 s
Your time
—
The rule this testsThe rules of differentiation
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Ten questions from Derivatives & Second-Order Derivatives, at your own pace.

Practise this chapter →

Ten questions from Derivatives & Second-Order Derivatives, at your own pace.