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Determinants, Adjoint & Inverse · Question 5 of 87

Question 5

EasyOriginal question

What is ∣25−103400−2∣\begin{vmatrix}2 & 5 & -1 \\ 0 & 3 & 4 \\ 0 & 0 & -2\end{vmatrix}?

Options for question 5

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. Every element below the leading diagonal is 0. Expanding down column 1 leaves 2∣340−2∣2\begin{vmatrix} 3 & 4 \\ 0 & -2 \end{vmatrix}.

  2. =2(−6−0)=−12= 2(-6 - 0) = -12: the product of the diagonal elements 2×3×(−2)2 \times 3 \times (-2).

Worth noting

3 adds the diagonal elements; a triangular determinant is their product.

Concept
Determinant of a triangular matrix
Typical time
60 s
Your time
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The rule this testsThe determinant of a matrix
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Ten questions from Determinants, Adjoint & Inverse, at your own pace.

Practise this chapter →

Ten questions from Determinants, Adjoint & Inverse, at your own pace.