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Determinants, Adjoint & Inverse · Question 40 of 87

Question 40

MediumOriginal question

For A=[4102−3512−1]A = \begin{bmatrix}4 & 1 & 0 \\ 2 & -3 & 5 \\ 1 & 2 & -1\end{bmatrix}, what is a21A21+a22A22+a23A23a_{21}A_{21} + a_{22}A_{22} + a_{23}A_{23}, where AijA_{ij} is the cofactor of aija_{ij}?

Options for question 40

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. Elements of a row times their own cofactors add up to the determinant.

  2. The cofactors of row 2 are 11, −4-4 and −7-7, so the sum is 2(1)+(−3)(−4)+5(−7)=−212(1) + (-3)(-4) + 5(-7) = -21.

Worth noting

0 is what elements of one row times the cofactors of a different row give.

Concept
Expanding a determinant along a row
Typical time
90 s
Your time
—
The rule this testsMinors and cofactors
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Ten questions from Determinants, Adjoint & Inverse, at your own pace.

Practise this chapter →

Ten questions from Determinants, Adjoint & Inverse, at your own pace.