How many solutions does the system $3x + y = 4$, $x + 2y = 3$ have?

Explanation

1. 01

   $|A| = 5$. It is not 0, so $A^{-1}$ exists and the solution is unique.

2. 02

   $(\operatorname{adj} A)B = \begin{bmatrix}5 \\ 5\end{bmatrix}$.