What is $\frac{d}{dx}\left(\sqrt{x^{3} + 1}\right)$?

Explanation

1. 01

   $\frac{d}{dx}\sqrt{u} = \frac{u'}{2\sqrt{u}}$ with $u = 1 + x^{3}$.

2. 02

   $\frac{3x^{2}}{2\sqrt{1 + x^{3}}}$.