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Chain Rule, Log Differentiation & Rate of Change · Question 4 of 130

How far is the particle from the point at the start?

Question 4

EasyOriginal question

A particle's distance from a point after tt seconds is s=t2+16s = \sqrt{t^{2} + 16} metres.

How far is the particle from the point at the start?

Options for question 4

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. At t=0t = 0: s=16s = \sqrt{16}.

  2. 4 m.

Worth noting

16 is under the square root.

Concept
Reading a position function
Typical time
90 s
Your time
—
The rule this testsThe chain rule
Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.

Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.