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Chain Rule, Log Differentiation & Rate of Change · Question 15 of 130

At what time is the particle momentarily at rest?

Question 15

MediumOriginal question

A particle's distance from a point after tt seconds is s=t2+16s = \sqrt{t^{2} + 16} metres.

At what time is the particle momentarily at rest?

Options for question 15

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. At rest means tt2+16=0\frac{t}{\sqrt{t^{2} + 16}} = 0.

  2. That happens only at t=0t = 0.

Worth noting

t=4t = 4 makes the two terms under the root equal; it does not make the velocity 0.

Concept
Velocity as a rate of change
Typical time
120 s
Your time
—
The rule this testsThe chain rule
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