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Chain Rule, Log Differentiation & Rate of Change · Question 29 of 130

Question 29

EasyOriginal question

What is ddx(sin⁡−1(2x))\frac{d}{dx}\left(\sin^{-1}{\left(2 x \right)}\right) for ∣x∣<12\lvert x \rvert < \frac{1}{2}?

Options for question 29

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. ddxsin⁡−1u=u′1−u2\frac{d}{dx}\sin^{-1} u = \frac{u'}{\sqrt{1 - u^{2}}} with u=2xu = 2x.

  2. 21−4x2\frac{2}{\sqrt{1 - 4x^{2}}}.

Worth noting

11−4x2\frac{1}{\sqrt{1 - 4x^{2}}} forgets the factor 2 from the inside.

Concept
Differentiating an inverse trigonometric function
Typical time
60 s
Your time
—
The rule this testsDerivatives of inverse trigonometric functions
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Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.

Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.