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Chain Rule, Log Differentiation & Rate of Change · Question 66 of 130

Question 66

MediumOriginal question

What is ddx(log⁡(tan⁡x+sec⁡x))\frac{d}{dx}\left(\log{\left(\tan x + \sec x \right)}\right) for 0<x<π20 < x < \frac{\pi}{2}?

Options for question 66

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. u′u\frac{u'}{u} with u=sec⁡x+tan⁡xu = \sec x + \tan x, u′=sec⁡xtan⁡x+sec⁡2x=sec⁡x(tan⁡x+sec⁡x)u' = \sec x\tan x + \sec^{2} x = \sec x(\tan x + \sec x).

  2. sec⁡x(sec⁡x+tan⁡x)sec⁡x+tan⁡x=sec⁡x\frac{\sec x(\sec x + \tan x)}{\sec x + \tan x} = \sec x.

Worth noting

1sec⁡x+tan⁡x\frac{1}{\sec x + \tan x} stops before multiplying by u′u'.

Concept
Exponential and logarithm inside a chain
Typical time
90 s
Your time
—
The rule this testsExponential and logarithmic functions
Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.

Practise this chapter →

Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.