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Chain Rule, Log Differentiation & Rate of Change · Question 92 of 130

Question 92

MediumOriginal question

If f(x)=(x+1)(x+2)(x+3)(x+4)f(x) = \frac{(x + 1)(x + 2)}{(x + 3)(x + 4)}, what is f′(0)f'\left(0\right)?

Options for question 92

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. log⁡y=log⁡(x+1)+log⁡(x+2)−log⁡(x+3)−log⁡(x+4)\log y = \log(x + 1) + \log(x + 2) - \log(x + 3) - \log(x + 4), so at 0, y′y=1+12−13−14=1112\frac{y'}{y} = 1 + \frac{1}{2} - \frac{1}{3} - \frac{1}{4} = \frac{11}{12}.

  2. y(0)=212=16y(0) = \frac{2}{12} = \frac{1}{6}, so f′(0)=16×1112=1172f'(0) = \frac{1}{6} \times \frac{11}{12} = \frac{11}{72}.

Worth noting

2572\frac{25}{72} adds 13\frac{1}{3} and 14\frac{1}{4}; the factors below the line enter with a minus sign.

Concept
Logarithmic differentiation of a quotient
Typical time
90 s
Your time
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The rule this testsLogarithmic differentiation
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Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.

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Ten questions from Chain Rule, Log Differentiation & Rate of Change, at your own pace.