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Homogeneous & Linear Differential Equations · Question 73 of 120

Question 73

MediumOriginal question

What is the integrating factor of ydxdy−x=2y3y\frac{dx}{dy} - x = 2y^{3}?

Options for question 73

Show the answer and explanation
CorrectNot quiteAnswer D

Correct answer: D

Explanation

  1. Divide by yy: dxdy−1yx=2y2\frac{dx}{dy} - \frac{1}{y}x = 2y^{2}, linear in xx with P=−1yP = -\frac{1}{y}.

  2. e−∫dyy=e−log⁡y=1ye^{-\int \frac{dy}{y}} = e^{-\log y} = \frac{1}{y}.

Worth noting

yy is the factor for +xy+\frac{x}{y}; the minus sign turns it into 1y\frac{1}{y}.

Concept
The integrating factor for \(\frac{dx}{dy} + Px = Q\)
Typical time
90 s
Your time
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The rule this testsLinear equations and the integrating factor
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Ten questions from Homogeneous & Linear Differential Equations, at your own pace.

Practise this chapter →

Ten questions from Homogeneous & Linear Differential Equations, at your own pace.