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Homogeneous & Linear Differential Equations · Question 85 of 120

Question 85

HardOriginal question

What is the integrating factor of xlog⁡xdydx+y=2log⁡xx\log x\frac{dy}{dx} + y = 2\log x?

Options for question 85

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. In the form dydx+Py=Q\frac{dy}{dx} + Py = Q, P=1xlog⁡xP = \frac{1}{x \log x}.

  2. The factor is e∫P dx=log⁡xe^{\int P\,dx} = \log x.

Worth noting

xlog⁡xx\log x is the coefficient of dydx\frac{dy}{dx}; dividing by it gives P=1xlog⁡xP = \frac{1}{x\log x}.

Concept
The integrating factor
Typical time
120 s
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The rule this testsLinear equations and the integrating factor
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Ten questions from Homogeneous & Linear Differential Equations, at your own pace.

Practise this chapter →

Ten questions from Homogeneous & Linear Differential Equations, at your own pace.