What is the domain of $\sin^{-1}(2x - 1)$ ?

[-1, 1]

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[-1, 0]

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[0, 1]

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[0, 2]

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Show the answer and explanation

CorrectNot quiteAnswer C

Correct answer: C

The input of the inverse function must lie in its domain: $-1 \le 2x - 1 \le 1$ .
$0 \le 2x \le 2$ , so $0 \le x \le 1$ .

Worth noting

$[-1, 1]$ is the range allowed for $2x - 1$ , not for $x$ .

Ten questions from Inverse Trigonometric Functions, at your own pace.

Ten questions from Inverse Trigonometric Functions, at your own pace.

What is the domain of sin⁡−1(2x−1)\sin^{-1}(2x - 1)sin−1(2x−1)?