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Inverse Trigonometric Functions · Question 36 of 120

Question 36

EasyOriginal question

What is the principal value of tan⁡−1(3)\tan^{-1}\left(\sqrt{3}\right)?

Options for question 36

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. Find the angle θ\theta in the branch (−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right) with tan⁡θ=3\tan \theta = \sqrt{3}.

  2. That angle is π3\frac{\pi}{3}.

Worth noting

tan⁡π6=13\tan \frac{\pi}{6} = \frac{1}{\sqrt{3}}; 3\sqrt{3} is tan⁡π3\tan \frac{\pi}{3}.

Concept
Principal value
Typical time
60 s
Your time
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The rule this testsPrincipal values
Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.

Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.