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Inverse Trigonometric Functions · Question 20 of 120

What is f(1/4) for this f(x) = sin^-1(2x - 1)?

Question 20

MediumOriginal question

Let f(x)=sin⁡−1(2x−1)f(x) = \sin^{-1}(2x - 1).

What is f(14)f\left(\frac{1}{4}\right) for this f(x)=sin⁡−1(2x−1)f(x) = \sin^{-1}(2x - 1)?

Options for question 20

Show the answer and explanation
CorrectNot quiteAnswer B

Correct answer: B

Explanation

  1. 2×14−1=−122 \times \frac{1}{4} - 1 = -\frac{1}{2}.

  2. sin⁡−1(−12)=−π6\sin^{-1}\left(-\frac{1}{2}\right) = -\frac{\pi}{6}.

Worth noting

π6\frac{\pi}{6} loses the sign of −12-\frac{1}{2}.

Concept
Principal value
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120 s
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Ten questions from Inverse Trigonometric Functions, at your own pace.

Practise this chapter →

Ten questions from Inverse Trigonometric Functions, at your own pace.