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Matrices · Question 80 of 106

Question 80

MediumOriginal question

If A=[2−1]A = \begin{bmatrix}2 \\ -1\end{bmatrix} and B=[31]B = \begin{bmatrix}3 & 1\end{bmatrix}, what is (AB)′(AB)'?

Options for question 80

Show the answer and explanation
CorrectNot quiteAnswer C

Correct answer: C

Explanation

  1. AB=[62−3−1]AB = \begin{bmatrix}6 & 2 \\ -3 & -1\end{bmatrix}, a 2 × 2 matrix.

  2. Its transpose is [6−32−1]\begin{bmatrix}6 & -3 \\ 2 & -1\end{bmatrix}, which is B′A′B'A', as the reversal law says.

Worth noting

[5]\begin{bmatrix}5\end{bmatrix} is A′B′A'B', a 1 × 1 matrix: the order of the transposes was not reversed.

Concept
The reversal law for transposes
Typical time
90 s
Your time
—
The rule this testsThe transpose
Practise this chapter →

Ten questions from Matrices, at your own pace.

Practise this chapter →

Ten questions from Matrices, at your own pace.