What is the maximum value of $f(x) = 3 - \lvert x + 1 \rvert$?

Explanation

1. 01

   $\lvert x + 1 \rvert \ge 0$, so $f(x) \le 3$.

2. 02

   At $x = -1$, $f = 3$: the maximum value is 3. There is no minimum.