What is the additive inverse of 5 modulo 12, written as one of $0, 1, \dots, 11$?

Explanation

1. 01

   The additive inverse of $a$ is the number $b$ with $a + b \equiv 0 \pmod{12}$.

2. 02

   $5 + 7 = 12 \equiv 0$, so it is 7.