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Normal Distribution · Question 52 of 68

Question 52

MediumOriginal question

Marks in an exam are normal with mean 60 and standard deviation 10. What percentage of students score more than 75? (Take P(0<Z<1.5)=0.4332P(0 < Z < 1.5) = 0.4332.)

Options for question 52

Show the answer and explanation
CorrectNot quiteAnswer A

Correct answer: A

Explanation

  1. z=75−6010=1.5z = \frac{75 - 60}{10} = 1.5.

  2. P(Z>1.5)=0.5−0.4332=0.0668P(Z > 1.5) = 0.5 - 0.4332 = 0.0668, so 6.68% of students.

Worth noting

93.32% is the share scoring less than 75.

Concept
The share above a value
Typical time
90 s
Your time
—
The rule this testsUsing the normal distribution
Practise this chapter →

Ten questions from Normal Distribution, at your own pace.

Practise this chapter →

Ten questions from Normal Distribution, at your own pace.